IN C$++$ PLEASE I need help outputting the code correctly as seen in the image. The code should read two node IDs from the console $($one per line$).$ Then, it must list the IDs of the resistors that are directly connected to the two nodes. For example, if the input is

N$1$

N$2$

then the output should be

R$1$

If the nodes are not adjacent $($and therefore no resistors are connected to both nodes$),$ a message should be printed as in the following example. Input:

N$1$

N$5$

Output:

No resistors found.

My Code:

#include

#include

#include

using namespace std;

struct Resistor $\{$

string ID;

double resistance;

$\}$;

struct Node $\{$

string ID;

bool ground;

vector connections; $//$ Change vector type to Resistor$*$

$\}$;

void find$\_$resistors$($string n$1,$ string n$2,$ vector& nodes$)\{$

bool found $=$ false;

for $($const auto& node : nodes$)\{$

if $($node$.$ID $==$ n$1||$ node.ID $==$ n$2)\{$

for $($const auto& connection : node.connections$)\{$

for $($const auto& other$\_$node : nodes$)\{$

if $($other$\_$node.ID $==$ n$1||$ other$\_$node.ID $==$ n$2)\{$

if $($other$\_$node.ID $!=$ node.ID$)\{$

for $($const auto& other$\_$connection : other$\_$node.connections$)\{$

if $($connection $==$ other$\_$connection$)\{$

cout $$ connection$->$ID ;

found $=$ true;

$\}$

$\}$

$\}$

$\}$

$\}$

$\}$

$\}$

$\}$

if $(!$found$)\{$

cout No resistors found.";

$\}$

cout $$ endl;

$\}$

int main$()\{$

string n$1,$ n$2$;

$//$ Read two node IDs from cin

cin $>>$ n$1>>$ n$2$;

$//$ Resistors

Resistor r$1=\{"$R$1",2200\mathrm{.}0\}$;

Resistor r$2=\{"$R$2",4700\mathrm{.}0\}$;

Resistor r$3=\{"$R$3",10000\mathrm{.}0\}$;

Resistor r$4=\{"$R$4",3300\mathrm{.}0\}$;

Resistor r$5=\{"$R$5",4700\mathrm{.}0\}$;

Resistor r$6=\{"$R$6",6800\mathrm{.}0\}$;

$//$ Nodes

vector nodes$(5)$;

nodes$[0].$ID $="$N$1"$;

nodes$[0].$ground $=$ true;

nodes$[0].$connections.push$\_$back$($&r$1)$;

nodes$[0].$connections.push$\_$back$($&r$3)$;

nodes$[1].$ID $="$N$2"$;

nodes$[1].$connections.push$\_$back$($&r$1)$;

nodes$[1].$connections.push$\_$back$($&r$2)$;

nodes$[2].$ID $="$N$3"$;

nodes$[2].$connections.push$\_$back$($&r$2)$;

nodes$[2].$connections.push$\_$back$($&r$4)$;

nodes$[2].$connections.push$\_$back$($&r$5)$;

nodes$[3].$ID $="$N$4"$;

nodes$[3].$connections.push$\_$back$($&r$3)$;

nodes$[3].$connections.push$\_$back$($&r$4)$;

nodes$[3].$connections.push$\_$back$($&r$6)$;

nodes$[4].$ID $="$N$5"$;

nodes$[4].$connections.push$\_$back$($&r$5)$;

nodes$[4].$connections.push$\_$back$($&r$6)$;

$//$ Call find$\_$resistors

find$\_$resistors$($n$1,$n$2,$ nodes$)$;

return $0$;

$\}$

$\{\begin{array}{ccc}\text{:}-=\text{I}\text{:}& 11=& \end{array}$

$x-$TIn$=$grad$||1||$

$11-=$

II$.\frac{?}{\text{b}\text{a}\text{r}}(3)$