Question: In each case, write the function f(z) in the form f(z)=u(x,y)+iv(x,y) : (a) f(z)=z^(3)+z+1 ; (b) f(z)=(/bar (z)^(2))/(z),(z ) != ( 0) . Suggestion: In
In each case, write the function
f(z)in the form
f(z)=u(x,y)+iv(x,y):\ (a)
f(z)=z^(3)+z+1;\ (b)
f(z)=(/bar (z)^(2))/(z),(z)
!=(
0).\ Suggestion: In part (b), start by multiplying the numerator and denominator by
/bar (z).\ Ans. (a)
f(z)=(x^(3)-3xy^(2)+x+1)+i(3x^(2)y-y^(3)+y);\ (b)
f(z)=(x^(3)-3xy^(2))/(x^(2)+y^(2))+i(y^(3)-3x^(2)y)/(x^(2)+y^(2)).

In each case, write the function f(z) in the form f(z)=u(x,y)+iv(x,y) : (a) f(z)=z3+z+1; (b) f(z)=zz2(z=0). Suggestion: In part (b), start by multiplying the numerator and denominator by z. Ans. (a) f(z)=(x33xy2+x+1)+i(3x2yy3+y); (b) f(z)=x2+y2x33xy2+ix2+y2y33x2y
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