In Exercise $2,$ you were to complete the function conditionally$\_$distribute$($seq$1,$ seq$2)$ with the given template:

def conditionally$\_$distribute$($seq$1,$ seq$2)$:

q$,$ count $=\{\},\{\}$ # NOT q $=$ count $=\{\}$

for i in seq$1$:

count$[$i$]=$ count.get$($i$,0)+1$

for i$,$ j in zip$($seq$1,$ seq$2)$:

q$[$i$][$j$]=\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

return q

At the beginning inside the above function, the variables q and count were assigned with two empty dictionaries.

It is wrong if we do so by writing q $=$ count $=\{\}.$ Why is it wrong? Choose the best answer.

Group of answer choices

The operator $=$ is right$-$associative

q and count will be alias of each other

The operator $=$ is left$-$associative

The operator $=$ is non$-$associative