Question: In Exercise 5.9 we determined that 6(1 - y2), 0 0, otherwise is a valid joint probability density function.

 In Exercise 5.9 we determined that6(1 - y2), 0 0, otherwiseis

In Exercise 5.9 we determined that

6(1 - y2), 0

0, otherwise

is a valid joint probability density function.

a valid joint probability density function.

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