In Josephus Problem the open form is

For even,J$(2$n$)=2($Jn$)-1$

For odd,J$(2$n$+1)=2($Jn$)+1$ where J$(1)=0$

Closed form is J$($n$)=2$l$+1$

And for $10$ people the $5$th person survive

Now find the Josephus problem recurrence open and closed form for anticlockwise direction and show that for $10$ people the $7$th person survive by the recurrence