In Lecture $1\mathrm{.}5,$ we discussed the flue gas desulfurization process to remove SO$2.$ While the primary scrubbing agent is CaCO$3,$MgCO$3$ is sometimes used; thus, the scrubbing reaction is $SO2+$MgCO$3$MgSO$3+CO2.$ For the plant described in Example $1,$ estimate the daily production of MgSO$3$ if MgCO$3$ is utilized as the scrubbing agent. The molecular weight of MgSO$3$ is $0\mathrm{.}104k\frac{g}{m}ol.$

$(9$ Points$)*[4)$

Your answer should be the daily production with a unit of "tonnesMgSO$3/$day$"$