Question: In MIPS Assembly Language: We define a rotation operation as a shift operation where most and least significant bits are not lost in the result.

In MIPS Assembly Language:

In MIPS Assembly Language: We define a rotation operation as a shiftoperation where most and least significant bits are not lost in the

We define a rotation operation as a shift operation where most and least significant bits are not lost in the result. For the left rotation, the value at the most significant bit (MSB) comes around to become the new least significant bit (LSB). Similarly, for the right rotation, the value at LSB comes around to become the new MSB. Your task is to write a MIPS program that will implement a rotation operation on a 64-bit register composed of two 32-bit registers. We will call these registers HI and LO. HI register corresponds to the 32 most significant bits, and LO register corresponds to the 32 least significant bits. You can use any $s or $t registers to represent HI and LO. Your program should follow the following layout: 1. Prompt the user to enter an initial integer value for the HI register 2. Prompt the user to enter an initial integer value for the LO register 3. Prompt the user to enter the direction of the rotation. You can assume that the user will always enter either 1,-1 or 0: a. If the user enters 1, rotate the 64-bit register left by 1. Repeat step 3. b. If the user enters -1, rotate the 64-bit register right by 1. Repeat step 3. c. If the user enters 0, print the value of HI and LO registers in hexadecimal. Terminate the program. i. Hint: Use syscall 34 Consider the following illustration of a right rotation operation on the 64-bit register with HI and LO registers having initial values of 45 and 7. Before Rotation: 0000 0000 0000 0000 0000 0000 0010 1101 0000 0000 0000 0000 0000 0000 0000 0111 HI LO After Rotation: 1000 0000 0000 0000 0000 0000 0001 0110 1000 0000 0000 0000 0000 0000 0000 0011 HI LO The final output of the program should look like the following: Enter integer value for HI register: 15 Enter integer value for LO register: 7 Enter rotation direction (0 to quit): 1 Enter rotation direction (0 to quit): 1 Enter rotation direction (0 to quit): -1 Enter rotation direction (0 to quit): -1 Enter rotation direction (0 to quit): -1 Enter rotation direction 10 to quit): -1 Enter rotation direction (0 to quit): 0 Value of HI: 0xc0000003 Value of LO: 0xc0000001 -- program is finished running -- We define a rotation operation as a shift operation where most and least significant bits are not lost in the result. For the left rotation, the value at the most significant bit (MSB) comes around to become the new least significant bit (LSB). Similarly, for the right rotation, the value at LSB comes around to become the new MSB. Your task is to write a MIPS program that will implement a rotation operation on a 64-bit register composed of two 32-bit registers. We will call these registers HI and LO. HI register corresponds to the 32 most significant bits, and LO register corresponds to the 32 least significant bits. You can use any $s or $t registers to represent HI and LO. Your program should follow the following layout: 1. Prompt the user to enter an initial integer value for the HI register 2. Prompt the user to enter an initial integer value for the LO register 3. Prompt the user to enter the direction of the rotation. You can assume that the user will always enter either 1,-1 or 0: a. If the user enters 1, rotate the 64-bit register left by 1. Repeat step 3. b. If the user enters -1, rotate the 64-bit register right by 1. Repeat step 3. c. If the user enters 0, print the value of HI and LO registers in hexadecimal. Terminate the program. i. Hint: Use syscall 34 Consider the following illustration of a right rotation operation on the 64-bit register with HI and LO registers having initial values of 45 and 7. Before Rotation: 0000 0000 0000 0000 0000 0000 0010 1101 0000 0000 0000 0000 0000 0000 0000 0111 HI LO After Rotation: 1000 0000 0000 0000 0000 0000 0001 0110 1000 0000 0000 0000 0000 0000 0000 0011 HI LO The final output of the program should look like the following: Enter integer value for HI register: 15 Enter integer value for LO register: 7 Enter rotation direction (0 to quit): 1 Enter rotation direction (0 to quit): 1 Enter rotation direction (0 to quit): -1 Enter rotation direction (0 to quit): -1 Enter rotation direction (0 to quit): -1 Enter rotation direction 10 to quit): -1 Enter rotation direction (0 to quit): 0 Value of HI: 0xc0000003 Value of LO: 0xc0000001 -- program is finished running

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