Question: In one dimension, a particle's position as a function of time is given by x(t) = (1.12 m/s) t - (6.7 m/s) t. What

In one dimension, a particle's position as a function of time is

In one dimension, a particle's position as a function of time is given by x(t) = (1.12 m/s) t - (6.7 m/s) t. What is the magnitude of the acceleration of the particle in units of m/s? Enter a number with one digit behind the decimal point.

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