In order to work for a public transit company, drivers need to be drug free before...

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In order to work for a public transit company, drivers need to be drug free before starting their shifts. Assume that the percentage of drivers who actually use drugs is 4%, the same as the general population. The transit company randomly screens drivers before their shifts start. The drug-screening test has a false positive rate of 3% and a false negative rate of 2%. This means that a driver who uses drugs tests positive for them 98% of the time and a driver who does not use drugs tests negative for them 97% of the time. (a) What is the probability that a randomly chosen driver who tests positive for drugs actually uses drugs? (b) What is the probability that a randomly chosen driver who tests negative for drugs does not use drugs? In order to work for a public transit company, drivers need to be drug free before starting their shifts. Assume that the percentage of drivers who actually use drugs is 4%, the same as the general population. The transit company randomly screens drivers before their shifts start. The drug-screening test has a false positive rate of 3% and a false negative rate of 2%. This means that a driver who uses drugs tests positive for them 98% of the time and a driver who does not use drugs tests negative for them 97% of the time. (a) What is the probability that a randomly chosen driver who tests positive for drugs actually uses drugs? (b) What is the probability that a randomly chosen driver who tests negative for drugs does not use drugs?

Answer rating: 100% (QA)

a Probability of a positive test indicating drug use We can use Bayes theorem to solve this problem ... View the full answer