In$$physics$,$ the$$escape velocity$$is the minimum speed needed for an object to "break free" from the gravitational attraction of a massive body. The escape velocity from earth is about $40,270$ km$/$h $(25,020$ mph$).$ For a massive celestial object $($e$.$g$.,$ a star or planet$),$ the escape velocity at a given distance is given by the formula:

ve$=2$GMr

where ve is the escape velocity in meters per second, G$$ is the universal gravitational constant and is equal to $6\mathrm{.}67$x$10-11$ m$3/$kg$/$s$2,$ M is the mass of the object in kilograms, and r is radius of the object in meters.

QUESTION:$$ Enceladus has a mass of $1\mathrm{.}08$x$1020$ kg and a radius of $2\mathrm{.}521$x$105$ meters.$$ What is the minimum speed $($in meters per second$)$ that the plumes must travel to escape the gravity of Enceladus? Round to the nearest whole number.