In Problems $21-40,$ perform the indicated operations using one byte to store each integer and two's complement form for negatives. Answer in binary and decimal.

$21.{27}_{10}+{50}_{10}$

$22.{14}_{10}+{83}_{10}$

$23.{53}_{10}+{16}_{10}$

$24.{24}_{10}+{72}_{10}$

$25.{14}_{10}+(-{72}_{10})$

$26.{46}_{10}+(-{53}_{10})=$

$27.-{11}_{10}+{61}_{10}$

$28.-{33}_{10}+{79}_{10}-$

$29.-{22}_{10}+(-{55}_{10})$

$30.-{74}_{10}+(-{17}_{10})$

$31.{27}_{10}-{50}_{10}$

$32.{14}_{10}-{83}_{10}$

$33.{53}_{10}-{16}_{10}$

$34.{24}_{10}-{72}_{10}$

$35.{14}_{10}-(-{72}_{10})$

$36.{46}_{10}-(-{53}_{10})$

$37.-{11}_{10}-{61}_{10}+(-{14}_{10})$

$38.-{33}_{10}-{79}_{10}+{41}_{10}$

$39.(-{22}_{10}-(-{55}_{10}))+{72}_{10}$

$40.(-{74}_{10}-(-{17}_{10}))+{50}_{10}$