in programming exercise 2, the class dataType was desifned and implemented to keep track of a data, but it has very limited operations. Redefine the class dataType so that it can perform the following operations on a data, in addition to the operations already defined.

Shoud Include

//***********************************************************************

Header file (dateType.h), Implementation files (dateTypeImp.cpp) Your main program, and your documentation files.

The dateType header file must contain the following functional prototypes:

void setDate(int, int, int);

void setMonth(int);

void setDay(int);

void setYear(int);

void print() const;

int numberOfDaysPassed();

int numberOfDaysLeft();

void incrementDays(int nDays);

int getMonth() const;

int getDay() const;

int getYear() const;

int getDaysInMonth();

bool isLeapYear();

dateType(int = 1, int = 1, int = 1900);

//******************************************************************

Should Include

//***************************************************************

Validate compilation of your header file with the following code. The test program will exercise all functions in the dateType class listed above.

#include

#include

#include "dateType.h"

using namespace std;

int main()

{

dateType date1(3, 15, 2008);

date1.print();

date1.setDate(10,10,2010);

date1.print();

date1.setMonth(12);

date1.setDay(12);

date1.setYear(2012);

date1.print();

cout << "Elapsed Days since 1/1/2012 = " << numberOfDaysPassed() << endl

<< " Days remaining in 2012 = " << numberOfDaysLeft() << endl;

date1.incrementDays(378); //add 378 days to the current date

cout << date1.getMonth() <<"/" << date1.getDay() << "/" << date1.getYear() << "/ ";

cout << "There are " << getDaysInMonth() << " days in this month "

<< "and this year " << isLeapYear() ? "is" : "is not"

<< " a leap year. ";

return 0;

}

//*********************************************************************************

The Result should look like below.

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Set date1= 3-15-2008

Change date1= 10-10-2010

Change month to 6 : 6-10-2010

Change day to 15: 6-15-2010

Change year to 2015: 6-15-2015

Elasped Day since 1/1 = 166

Days remaining in year: 199

Adding 366 days to 6-15-2015

The new Data is : 6/15/2016

There are 30 days in this month and this year is a leap year.

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