In python

I need help fixing my linked list since it doesn't seem to be working and using the same methods to create a doubly linked list

here's my code so far, thank you!! :)

# Implementing the node class class Node: def __init__(self, data = None, nextNode = None): self.data = data self.nextNode = nextNode def __str__(self): return str(self.data) def getData(self): return self.data def getNext(self): return self.nextNode

def setNext(self,newNext): self.nextNode = newNext # Implementing the linked lists class linkedLists: def __init__(self, head = None): self.head = None

def add(self, data): newNode = Node(data) if(self.head): newNode.setNextNode = self.head self.head = newNode else: self.head = newNode

def remove(self,data): current = self.head previous = None found = False while not found: if current.getData() == data: found = True else: previous = current current = current.getnextNode() if previous == None: self.head = current.getnextNode() else: previous.nextNode(current.getnextNode())

def size(self): current = self.head count = 0 while current != None: count = count + 1 current = current.getNext() return count

def search(self,data): current = self.head found = False while current != None and not found: found = True else: current = current.getnextNode() return found def insert(self,data): newNode = Node(data) newNode.setNext(self.head) self.head = newNode

def isEmpty(self): return self.head == None

def append(self):

# Big O run time:

#Implementing Doubly-Linked List class Node: def __int__(delf, data): self.data = data self.previous = None self.next = None

class doublyLinked: def __init__(self): self.head = None self.tail = None

def addNode(self, data): newNode = Node(data)