Question: In Python please: Now we want a way to make our monsters fight! Before two monsters can fight, we need to give 2 new class
In Python please:
Now we want a way to make our monsters fight!
Before two monsters can fight, we need to give 2 new class methods that update their stats. Implement a method for win_fight and lose_fight. Win_fight should add 5 to the monsters self.exp and reset their hp to max_hp. lose_fight should also reset their hp but only adds 1 exp to self.exp.
Now write a function that takes 2 instances of the monster class and makes them fight. This function should be defined outside the Monster class, i.e. it is not a Monster method. A fight goes as follows:
- The monster that entered as the first function goes first.
- Each monster takes a turn using one attack move. The monster selects this attack move from the strongest to the weakest in a circular function.
For example:
A monster has a dictionary of possible attack as follows:
[fire_storm: 3, double_hit: 4, earthquake: 2, ice_storm: 3]
Monster will select the following attacks:
| Round No | Move | Explanation |
|---|---|---|
| 1 | double_hit | Highest hit points |
| 2 | fire_storm | Same hit points as ice_storm but comes first alphabetically |
| 3 | ice_storm | |
| 4 | earthquake | |
| 5 | double_hit | |
| 6 | fire_storm | |
| 7 | ice_storm |
. And so on.
- An attack is always successful and will decrease the opponents hp by the given number of points in self.attacks dictionary. The monsters continue taking turns until their current hp becomes less than or equal to zero.
- At this point, the win_fight and lose_fight method should be invoked. Once this complete, return 3 things from the function.
- Round_number
- Monster that won (return the corresponding Monster object)
- List of attacks the monster used
Special Edge Case: If both monster only have wait as an attack, return
- -1 (round_number)
- None (for monster name that won)
- None (for list of attack that monster use)
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