In questions given below, determine the output produced by the lines of code using Visual Basic where Courier New is the font setting for the list box.

53. Dim fmtStr As String = "(0,-13}(1,-10}(2,-7:N0}" IstOutput.Items.Add("123456789012345678901234567890") IstOutput.Items.Add(String.Format(fmtStr, "Mountain", "Place", "Ht (ft)")) IstOutput.Items.Add(String.Format(fmtStr, "K2", "Kashmir", 28250))

54. Dim fmtStr As String = "{0,11} {1,-11}" 'Three spaces IstOutput.Items.Acid("12345678901234567890") IstOutput.Items.Add(String.Format(fmtStr, "College", "Mascot")) IstOutput.Items.Add(String.Format(fmtStr, "Univ. of MD", "Terrapins")) IstOutput.Items.Add(String.Format(fmtStr, "Duke", "Blue Devils"))

55. 'Elements in a 150 Pound Person Dim fmtStr As String = "{0,-7} {1,-7:N1} {2,-7:Pl}" 'Two spaces IstOutput.Items.Clear() IstOutput.Items.Add("12345678901234567890") IstOutput.Items.Add{String.Format(fmtStr, "Element", "Weight", "Percent")) IstOutput.Items.Add(String.Format(fmtStr, "Oxygen", 97.5, 97.5 / 150)) IstOutput.Items.Add(String.Format(fmtStr, "Carbon", 27, 27 / 150))

56. Dim fmtStr As String = "{0,10} {1,-10:CO}" 'Three spaces IstOutput.Items.Clear() IstOutput.Items.Add("12345678901234567890") IstOutput.Items.Add(String.Format(fmtStr, "Tuition")) IstOutput.Items.Add(String.Format(fmtStr, "College", "& Fees")) IstOutput.Items.Add(String.Format(fmtStr, "Stanford", 46300)) IstOutput.Items.Add(String.Format(fmtStr, "Harvard", 45278))

I want answers with outputs for all the four parts.