Question: In RSA, why is d computed as the multiplicative inverse of e mod (N) rather than the multiplicative inverse of e mod N? In other

In RSA, why is d computed as the multiplicative inverse of e mod (N) rather than the multiplicative inverse of e mod N? In other words, why do we need e d 1 mod (N) rather than e d 1 mod N?

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5. Develop a scenario comparing two PH programs and involving the use of a CBA.

4. Explain the strengths and weaknesses of each approach.

d. Describe any challenges in trying to communicate. If there were no challenges, explain why you think it was so easy.

3. Identify the methods used within each of the three approaches.