Question: In the below formula: S = v0 t a t^2 Distance is equal to the initial velocity multiplied by time plus one half acceleration times

In the below formula: S = v0 t a t^2 Distance is equal to the initial velocity multiplied by time plus one half acceleration times time squared. What is true about the acceleration in order for the formula to be accurate? Group of answer choices It has to be zero Neither of the other answers is correct It has to be constant

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