In the circuit below find the current I$3($in A$)$ when R$1=106,$ R$2=82,$ R$3=45,$ R$4=56,$ R$5=158,$ and V $=188$ V$.$ Be careful about the sign.

Hint:

Circuits can look very complicated, but at the same time one may be able to greatly simplify them. This is possible here. Please look at the vertical line connecting the points between R$1,$ R$2$ and R$3,$ R$4$: It does not have a resistance. This means that all four of these resitors are connected to the same point. It also means that R$2$ and R$4$ are in parallel. You can then go from there by finding other series and parallel combinations that you can simplify.