Question: In the code snippet below, the array arr is declared in line #7 with a size of 4 with 4 initial values also defined. However,

In the code snippet below, the array

arr

is declared in line #7 with a size of 4

with 4 initial values also defined.

In the code snippet below, the array arr is declared in line

However, in line #9 to #11, the arrays are accessed to be printed. The loop is

set at SIZE+2 in line #9 which means that we will access values beyond that of

the array. C++ does not check for out-of-bound access in an array.

Output printed from the loop in #9 to #11 is shown below.

#7 with a size of 4 with 4 initial values also defined.

Last two values are invalid because they are values beyond the array.

You will now define an array that will check for the array bounds.

Design an array called

myArray

according to this declaration.

However, in line #9 to #11, the arrays are accessed to be

Here is definition of empty constructor in line #13

printed. The loop is set at SIZE+2 in line #9 which means

Here is definition of constructor in line #11 specifying the upper bound of the

array

that we will access values beyond that of the array. C++ does

not check for out-of-bound access in an array. Output printed from the

loop in #9 to #11 is shown below. Last two values are

invalid because they are values beyond the array. You will now define

4 const int SIZE=4; 6 int main() int arr[SIZE] {3,14, 7,81); = 8 9, 10 for(int 1-0;1

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