In the depiction below explain why there is a problem with the addressing schemes.

A. 192.168.100.37/26 by given IP address, please find the following:

i) Subnetmask(1 Mark)

ii) Subnetwork(1Mark)

iii) Number of hosts per-subnet (1 Mark)

iv) Broadcast (1 Mark)

v) Number of Subnet (1 Mark)

B. Which are examples of supernetting [2 Marks] and why [ 3 Marks]

i) 10.10.0.0/12

ii) 10.10.0.0/16

iii) 10.10.0.0/21

iv) 172.19.0.0/12

v) 172.19.0.0/16

vi) 172.19.0.0/21

vii) 172.19.0.0/24

viii) 192.168.0.0/21

ix) 192.168.0.0/24