Question: In the following code fragment, assuming we have register r 1 as the base address for an array of 3 2 bit integers, the content

In the following code fragment, assuming we have register r1 as the base address for an array of 32 bit integers, the content of register r2 is stored in the array's third element.
str r2,[r1,+#12]/**(r1+12) r2*/

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