Question: In the following code section, the address of the first instruction is 00D469B4 in hexadecimal. begin: (667 instructors) j begin (423 instructors) end: add $t1,

 In the following code section, the address of the first instructionis 00D469B4 in hexadecimal. begin: (667 instructors) j begin (423 instructors) end:

In the following code section, the address of the first instruction is 00D469B4 in hexadecimal.

 begin: (667 instructors) j begin (423 instructors) end: add $t1, $t2, $t3 

Suppose the instruction j begin is executed by the processor shown in the diagram below.

Provide the values sent to the following ports:

  • Read address of Instruction Memory (in hexadecimal)
  • Control unit (in binary)
  • (Top left) Shift left 2 (in hexdecimal, pad the left with 00)

Also provide the output from the following ports/units:

  • PC adder (in hexadecimal)
  • Read data 1 of Registers (in hexadecimal)
  • Jump address (in hexadecimal)

as well as the following control signals:

  • MemRead (1 bit)
  • Branch (1 bit)
  • ALUSrc (1 bit)

If the value cannot be known (for example the output of data memory when it is written), or if it is a control signal that does not matter, mark it with an X. Please provide the answer as a sequence of number separated by comma, e.g, 00110, ABCD1234,X,0,11001,1234ABCD,1,X,0. Use uppercase letters for hexadecimal digits.

In the following code section, the address of the first instruction is 00D469B4 in hexadecimal. begin: (667 instructors) j begin (423 instructors) end: add $t1, $t2, $t3 Suppose the instruction j begin is executed by the processor shown in the diagram below. Provide the values sent to the following ports: Read address of Instruction Memory (in hexadecimal) Control unit (in binary) (Top left) Shift left 2 (in hexdecimal, pad the left with 00) Also provide the output from the following ports/units: PC adder (in hexadecimal) Read data 1 of Registers (in hexadecimal) Jump address (in hexadecimal) as well as the following control signals: MemRead (1 bit) Branch (1 bit) ALUSrc (1 bit) If the value cannot be known (for example the output of data memory when it is written), or if it is a control signal that does not matter, mark it with an X. Please provide the answer as a sequence of number separated by comma, e.g, 00110, ABCD1234,X,0,11001,1234ABCD,1,X,0. Use uppercase letters for hexadecimal digits. Jump address [310] Shift Instruction (250] (anih left 2) = len 28 o PC + 4 [3128] Branch Adder ALU 5x 5* o Add result PC Adder Shift left 2 RegDst Jump Branch MemRead | Instruction [3126] . MemtoReg Control ALUOp MemWrite ALUSrc RegWrite PC Read register 1 Read data 1 Read Instruction [2521] Read address II Instruction [2016] Instruction [310] Instruction | | Instruction (1511] X memory Zero ALU ALU Ler Address data Read result register 2 Write Read register data 2 Write data Registers ESX Eso Write Data data memory Instruction [15-] 16 Sian-) 32 extend ALU control Instruction [50] In the following code section, the address of the first instruction is 00D469B4 in hexadecimal. begin: (667 instructors) j begin (423 instructors) end: add $t1, $t2, $t3 Suppose the instruction j begin is executed by the processor shown in the diagram below. Provide the values sent to the following ports: Read address of Instruction Memory (in hexadecimal) Control unit (in binary) (Top left) Shift left 2 (in hexdecimal, pad the left with 00) Also provide the output from the following ports/units: PC adder (in hexadecimal) Read data 1 of Registers (in hexadecimal) Jump address (in hexadecimal) as well as the following control signals: MemRead (1 bit) Branch (1 bit) ALUSrc (1 bit) If the value cannot be known (for example the output of data memory when it is written), or if it is a control signal that does not matter, mark it with an X. Please provide the answer as a sequence of number separated by comma, e.g, 00110, ABCD1234,X,0,11001,1234ABCD,1,X,0. Use uppercase letters for hexadecimal digits. Jump address [310] Shift Instruction (250] (anih left 2) = len 28 o PC + 4 [3128] Branch Adder ALU 5x 5* o Add result PC Adder Shift left 2 RegDst Jump Branch MemRead | Instruction [3126] . MemtoReg Control ALUOp MemWrite ALUSrc RegWrite PC Read register 1 Read data 1 Read Instruction [2521] Read address II Instruction [2016] Instruction [310] Instruction | | Instruction (1511] X memory Zero ALU ALU Ler Address data Read result register 2 Write Read register data 2 Write data Registers ESX Eso Write Data data memory Instruction [15-] 16 Sian-) 32 extend ALU control Instruction [50]

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