In the following code snippet, where comments indicate line numbers:

uint$64\_$t x $=2$;

uint$64\_$t y $=5$;

uint$64\_$t mul$($uint$64\_$t a$,$ uint$64\_$t b$)\{$

uint$64\_$t e $=$ a $*$ b; $//$ L$0$

return e; $//$ L$1$

$\}$

uint$64\_$t comp$($uint$64\_$t n$)\{$

uint$64\_$t e $=0$; $//$ L$2$

uint$64\_$t f $=0$; $//$ L$3$

e $=$ mul$($x$,$ n$)$; $//$ L$4$

f $=$ mul$($n$,$ y$)$; $//$ L$5$

return e $+$ f; $//$ L$6$

$\}$

int main$()\{$

comp$(2)$; $//$ L$7$

$\}$

Draw the stack, and show where the base pointer $(\%$rbp$)$ and the stack pointer $(\%$rsp$)$ point right before L$4$ begins executing.

Draw the stack, and show where the base pointer $(\%$rbp$)$ and the stack pointer $(\%$rsp$)$ point right before the call instruction that transfers control to the mul function is executed $($that is$,$ after arguments have been placed in the appropriate registers$).$ What line of source code does the instruction pointer $(\%$rip$)$ correspond to in this case? Note that some lines of C can expand into multiple instructions; your answer should specify the line of C code that led to the compiler producing the instruction at the address pointed to by $\%$rip.

Draw the stack right after mul$$s prologue has finished executing. You can assume that mul was called from L$4.$

Draw the stack right after mul$$s epilogue has finished executing, but before the ret instruction has returned control to the caller. Also state what line of C source code the instruction pointer $(\%$rip$)$ corresponds to in this case. You should assume that mul was called from line L$4.$ Similar to part $($b$),$ your answer should specify the line of C that led to the instruction pointed to by $\%$rip being produced