In the following program, delete b will only call the base class destructor. The object of the derived class remains in memory because its destructor is never called. Which results in a memory leak.

class Base

$\{$

$$ public:

$$ ~Base$()$

$\{$

$$ cout $<<$ "Base Destructor

$"$;$$

$\}$

$\}$;

class Derived:public Base

$\{$

$$ public:

$$ ~Derived$()$

$\{$

$$ cout$<<$ "Derived Destructor

$"$;$$

$\}$

$\}$;$$

int main$()$

$\{$

$$ Base$*$ b $=$ new Derived; $//$ Upcasting

$$ delete b;

$\}$

Group of answer choices

True

False