in the following table:

$\backslash$table$[[$Activity$,\backslash$table$[[$Normal$],[$Time $($weeks$)]],\backslash$table$[[$Crash$],[$Time $($weeks$)]],\backslash$table$[[$Normal$],[$Cost$]],\backslash$table$[[$Total Cost$],[$with$],[$Crashing$]],$Immediate Predecessor$($s$)],[$A$,4,3,$$$2,200,$$$2,850,-],[$B$,2,1,$$$2,300,$$$3,100,-],[$C$,3,3,$$$500,$$$500,-],[$D$,8,4,$$$2,400,$$$2,720,$A$],[$E$,6,3,$$$1,000,$$$1,375,$B$],[$F$,3,2,$$$3,200,$$$4,700,$C$],[$G$,4,2,$$$1,600,$$$2,000,$D$,$ E$]]$

a$)$ Based on the given information regarding the activities for the project, the project length $=16$ weeks.

b$)$ The total cost required for completing this project on normal time $=$$$13,200.$

c$)$ For reducing the duration of the project by one week, the activity that should be crashed first is activity D $.$

The cost of the project based on the first activity selected for crashing will increase by $$80.$

d$)$ The maximum weeks by which the project can be reduced by crashing $=,$ weeks.

Total cost of crashing the project to minimum $($or maximum weeks possible$)=$$$1,495.$