In the single-phase half-controlled bridge rectifier shown below, the source voltage v, is 240 V rms....

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In the single-phase half-controlled bridge rectifier shown below, the source voltage v, is 240 V rms. The load resistance is R = 10 Q. (a) If the load inductance L is very large (load current constant), find the firing angle a so that the load current is i=15 A. (b) Sketch the voltage (VL) across the inductor for a = 60 (L is very large). (c) For L = 200 mH, assuming that the voltage across L is as in part (b), find approximately the peak-to- peak ripple in the load current i.. di (Hint: Integrate equation for the inductor: L=v; io is not to be taken as a constant now) dt Vs Kr. T KT, T3 D4 AD m + R L In the single-phase half-controlled bridge rectifier shown below, the source voltage v, is 240 V rms. The load resistance is R = 10 Q. (a) If the load inductance L is very large (load current constant), find the firing angle a so that the load current is i=15 A. (b) Sketch the voltage (VL) across the inductor for a = 60 (L is very large). (c) For L = 200 mH, assuming that the voltage across L is as in part (b), find approximately the peak-to- peak ripple in the load current i.. di (Hint: Integrate equation for the inductor: L=v; io is not to be taken as a constant now) dt Vs Kr. T KT, T3 D4 AD m + R L

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