Question: The W= 5 kN/m uniformly distributed loaded composite steel beam is shown in Figure (a). The steel composite section consists of two steel plates,

The W= 5 kN/m uniformly distributed loaded composite steel beam is shown 

in Figure (a). The steel composite section consists of two steel plates,

 each with dimensions of 229 x 30mm and a universal beam section 

The W= 5 kN/m uniformly distributed loaded composite steel beam is shown in Figure (a). The steel composite section consists of two steel plates, each with dimensions of 229 x 30mm and a universal beam section Section1 (See Table 1) are bolted together to form the composite section as shown in Figure (b). The 16 mm diameter bolts are spaced longitudinally every 150 mm. The sectional properties are given in Figure (c) and Table 1. The modulus of elasticity for steel is 200 GPa. a a P Steel plate I UB Section 10 m Figure (a) Simply supported beam w kN/m Steel plate (b) Section a-a (dimensions not to scale) d X E y. (c) UB Section Figure (b) Section a-a & (c) UB section Section 1 610UB125 2 610UB113 3 610UB101 4 530UB92.4 5 530UB82 X Table 1. Sectional properties UB Section d y A bf ti lxe mm mm mm (x108 mm) mm 16000 612 229 19.6 986 14500 607 228 17.3 875 13000 602 228 14.8 10.6 761 11800 533 209 15.6 10.2 554 10500 528 209 13.2 9.6 477 tu mm 11.9 11.2 lyo (x108 mm) 39.3 34.3 29.3 23.8 20.1 a) Determine the moment of inertia Ixx with respect to the centroidal axes. Ixx = ?x10 mm4 b) Determine the maximum deflection. Please insert - sign if the deflection is downward. Yosx = = ? mm

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