In this experiment you will get to test Newton's 2nd Law: F = Ma. You will experimentally measure the force (hanging mass m2's weight) that causes the glider ( m1) to accelerate to the right as m2 falls. Note that throughout the experiment, the mass of the system (M = m1 + m2) remains constant. Please see the attached images of the setup, the glider and a video demonstrating the experiment. The data collected is also attached. To find the acceleration, you will first find the averge velocity. Measure D between photogates, then divide by the time taken. Vave = Vf+ vi 2 You make sure the glider starts from rest (v; = 0 m), so from the average velocity found earlier, find V Now find the acceleration, a = vf-vi t S Transfer one disc (5g) from m to m2, then repeat the steps above to find a Plot a graph of F (= m2g) versus a. Find the slope and relate it to the mass of the system Find the percent error between your estimated mass of the system and the known mass of the system (what you kept fixed). Write a regular lab report and comment of sources of error. M (g) m1 (g) m2 (g) Time (s) D (cm) 233.86 213.86 20 20 2.1347 69.7 233.86 208.86 25 1.5746 233.86 203.86 30 1.341 233.86 198.86 35 1.182 233.86 193.86 40 1.0342 99 5359 STATION 3 ID: NSFLAB PASSWORD REASON LOGGER PRO 3.15 78 150 3 4 5 6 7 8 9 160 1 3 4 5 6 8 9 170 2 4 9 180 1 3 4 5 6 8 9 190 -D- Mi a = ? th Mi (1 frictionles) Vare = Since v = 0 M/5 + Now, a = 2 f M2 ; (a = const;) - = 2x v ave 44 mig t i = a exp a exp = 22 t ave t F = T = , F = T = m, a,, =m, a - (1) m mzg EF y = T-mg = - may -m2 T-mg = -Ma -(2) Substitute T from eq^ -(1) into eq^ (2) ma-mg a th = M2 -mza mitm2 g