Question: In this problem we are using the group (G, *) = (U28, 28) and the subgroup H = {1, 15}. U28 {1, 3, 5,

In this problem we are using the group (G, *) = (U28,28) and the subgroup H = {1, 15}. U28 {1, 3, 5,

In this problem we are using the group (G, *) = (U28, 28) and the subgroup H = {1, 15}. U28 {1, 3, 5, 9, 11, 13, 15, 17, 19, 23, 25, 27} and the right cosets of H in U28 are the columns of the following table. H1 H9 H3 H11 H5 H13 1 9 3 11 5 13 15 23 17 25 19 27 (Remember that there are several way of naming each coset and I have chosen one way.) Below is the table for the operation on G/H = U28/H, the set of right cosets. (Recall that Ha Hb = H(a 28 b).) In your answers use the names for the cosets which are column headings of the table above. H1 H9 H3 H11 H5 H1 H13 H9 H3 H11 H5 H13

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