In this problem we consider the resonance curve for a circuit with electrical components $L,R,$ and $C$ and resonant frequency ${}_0.$

For given values of $R$ and $C,$ if you double the value of $L,$ how does the new resonance curve differ from the original one?

View Available Hint$($s$)$

Both the peak height and peak frequency double.

The peak height will be half as great, and the peak frequency will double.

The peak height won't change, and the peak frequency will be $\frac{1}{\sqrt[\phantom{2}]{2}}$ times as great.

The peak height won't change, and the peak frequency will be half as great.

Part B

For given values of $R$ and $C,$ if you double the value of $L,$ how does the new rms current at resonance $I_{rms}$ differ from its original value? Assume that the voltage amplitude of the ac source is the same.

View Available Hint$($s$)$

$I_{rms}$ is twice as great.

$I_{rms}$ is half as great.

$I_{rms}$ is $\frac{1}{\sqrt[\phantom{2}]{2}}$ times as great.

$I_{rms}$ is unchanged.