In this problem, we will use what we have learned about simple rotational and vibrational spectroscopy to examine an exotic diatomic molecule: Xe2. While there is no appreciable chemical bonding between two Xe atoms because they are noble gases, they still have a slight interaction through induced-dipole forces. The functional form of this interaction is often modeled with what is called a 6-12 or Lennard-Jones potential: V(r) = 4 r 12 r 6 V(r) where r is the distance between the two atoms, and the parameters and are unique to the particular molecular system being studied. For Xe2, = 4.06 A and = 159.164 cm1 = 3.162 1021J b.) The rotational constant for Xe2 is: Be = 1.18 102 cm1. What is the equilibrium bond distance, re, of Xe2? The bond length of I2 is 266.7 pm. Does your answer match with your chemical intuition? Explain