In this program, you will take command-line arguments of 10 numbers, which are assumed to be integers, and find the median or the average of them. The average of the array should be a floating point number (double). Before the numbers on the command line, there will be an argument that indicates whether to find the median (m) or average (-a), if the user entered an invalid option or incorrect number of arguments, the program should display an error message. To find the median of an array, use the selection_sort function provided to sort the array, the median is the number that is halfway into the array: a[n/2], where n is the number of the elements in array a.

Use this selection_sort function provided below in the program (do not modify any of the provided function given below):

void selection_sort(int a[], int n)

{

int i, largest = 0, temp;

if (n == 1)

return;

for (i = 1; i < n; i++)

if (a[i] > a[largest])

largest = i;

if (largest < n - 1) {

temp = a[n-1];

a[n-1] = a[largest];

a[largest] = temp;

}

selection_sort(a, n - 1);

}

Example input and output:

./a.out

echo 'Expected:'

echo 'Invaild number of arguments. Usage: ./a.out -a (or -m) followed by 10 integers'

./a.out -a 10 9 23 24 559 20 84 12 48 98

echo 'Expected:'

echo 'Average: 88.700000'

./a.out -m 8 12 42 10 89 4 1 39 102 3

echo 'Expected:'

echo 'Median: 12'

./sort -h 8 12 42 10 89 4 1 39 102 3

echo 'Expected:'

echo 'Invalid option'

1) Name the program command_line.c

2) Use strcmp function to process the first command line argument.

3) Use atoi function in to convert a string to integer form.