In this question consider the lawn mower as your system. a man pushes a $20$ kilogram lawn mower with constant force $L$ of $100$ newtons directed along the handle which is constantly at an angle of $53$ with the horizontal. The horizontal acceleration of the lawn mower along the ground is $1\mathrm{.}6me\frac{t}{se{c}^2}$ to the right as the lawn mower moves horizontally to the right along the ground. The lawnmower has no vertical acceleration. There is a h zontal frictional force f between the mower and the ground and the ground also exerts an upward normal force N on the mower.

A$.$ What is the weight, in newtons, of the lawn mower?

B$.$ Resolve the force, $L=100$ newtons that the man exerts on the lawn mower into horizontal and vertical components $L_x$ and $L_{,}$ respectively. Use this diagram.

C$.$ Isolate the lawn mower and draw its force diagram, showing all the forces acting on it$.$ In this diagram replace The mans force $L$ by its components $L_{}$ and $L_{}$ whose values you found in part B$.$ Remember to include $L_x$ and $L_{}$ in the subsequent parts of this problem.

D$.$ Draw the acceleration diagram. Note that the value of $a_x$ was given above and that there is no vertical acceleration. In other words state the values of $a_x$ and $a_y.$

E$.$ USe $F_y=m{a}_y$ to find the normal force $N$ exerted by the ground on the lawn mower.

F$.$ USe $F_x=m{a}_x$ to find the frictional force $f$ exerted by the ground on the lawn mower.

G$.$ Find the coefficient of friction $$

H$.$ Find the total force, magnitude and direction, that the ground exerts on the lawn mower.

I. To how many g$\text{'}$s does the lawn mower's acceleration of $1\mathrm{.}6\frac{m}{s^2}$ correspond?