In this question, you will practice writing assembly programs using the RISCV assembly code. Since the RISCV assembly code is very similar to the MIPS assembly code, you may find the references in COD helpful. In all cases, assume the variables are stored in the following registers: C Declaration Variable Register unsigned x ao unsigned y y a1 unsigned z a2 unsigned a [20] unsigned* P a4 char c [20] a5 poN a3 A.3.1 Arithmetic and logic operations Implement the following C code segment as RISCV assembly code. z = x - y - z y = x & OxF0 + z & Ox04 y = a[2] + 9 y = a[a[0] + y) z = ((unsigned) c[1]) + x x = y % 4 A.3.2 Assembly to C Convert the following assembly code segment into C code: addi a2, ai, 9 add a0, a2, a2 addi to, a3, 4 lw a0, 0(to) lb lb and to, 4(a5) ti, 7(a5) a0, to, t1 lw to, 0(a3) lw to, 4(10) to, 4(a3) SW A.3.3 Branches and Jumps Implement the following C code segment as RISCV assembly code. if (x == y) { z = x+1; } else { z = a[2]; } = if (x z) { a[x] a[x] + 1; } else { a[x] = a[x] 1; } for (x = 0; x 0) { a[x] = y; y++; } In this question, you will practice writing assembly programs using the RISCV assembly code. Since the RISCV assembly code is very similar to the MIPS assembly code, you may find the references in COD helpful. In all cases, assume the variables are stored in the following registers: C Declaration Variable Register unsigned x ao unsigned y y a1 unsigned z a2 unsigned a [20] unsigned* P a4 char c [20] a5 poN a3 A.3.1 Arithmetic and logic operations Implement the following C code segment as RISCV assembly code. z = x - y - z y = x & OxF0 + z & Ox04 y = a[2] + 9 y = a[a[0] + y) z = ((unsigned) c[1]) + x x = y % 4 A.3.2 Assembly to C Convert the following assembly code segment into C code: addi a2, ai, 9 add a0, a2, a2 addi to, a3, 4 lw a0, 0(to) lb lb and to, 4(a5) ti, 7(a5) a0, to, t1 lw to, 0(a3) lw to, 4(10) to, 4(a3) SW A.3.3 Branches and Jumps Implement the following C code segment as RISCV assembly code. if (x == y) { z = x+1; } else { z = a[2]; } = if (x z) { a[x] a[x] + 1; } else { a[x] = a[x] 1; } for (x = 0; x 0) { a[x] = y; y++; }