In Units 6.3.1-3 we analyzed how error accumulates when computing a dot product of x and y of size m in the order indicated by = ( ( ( ( 0 0 + 1 1 ) + 2 2 ) + ) + m 1 m 1 ) . Let's illustrate an alternative way of computing the dot product: For m = 2 : = 0 0 + 1 1 For m = 4 : = ( 0 0 + 1 1 ) + ( 2 2 + 3 3 ) For m = 8 : = ( ( 0 0 + 1 1 ) + ( 2 2 + 3 3 ) ) + ( ( 4 4 + 5 5 ) + ( 6 6 + 7 7 ) ) and so forth. Analyze how under the SCM error accumulates and state backward stability results. You may assume that m is a power