Question: #include Dictionary.h bool verbose = false; int numWords = 0; void SolveBoard(string board[4][4], Dictionary& dict, Dictionary& wordsFound, bool printBoard); int main() { string board[4][4]; Dictionary

 #include "Dictionary.h" bool verbose = false; int numWords = 0; void

SolveBoard(string board[4][4], Dictionary& dict, Dictionary& wordsFound, bool printBoard); int main() { string

board[4][4]; Dictionary dict("C:\\PathToDictionary\\dictionary.txt"); cout > word; if (dict.isWord(word)) { cout #pragma once

#include #include #include using namespace std; struct Node { // Your data

structure goes here }; class Dictionary { public: Dictionary(); Dictionary(string file); void

#include "Dictionary.h" bool verbose = false; int numWords = 0; void SolveBoard(string board[4][4], Dictionary& dict, Dictionary& wordsFound, bool printBoard); int main() { string board[4][4]; Dictionary dict("C:\\PathToDictionary\\dictionary.txt"); cout > word; if (dict.isWord(word)) { cout  

#pragma once #include  #include  #include  using namespace std; struct Node { // Your data structure goes here }; class Dictionary { public: Dictionary(); Dictionary(string file); void addWord(string word); bool isWord(string word); bool isPrefix(string word); int wordCount(); private: Node* root; int numWords; // Any private methods you need/want };

dictonary

ally beta cool deal else flew good hope ibex

Assignment 3 - Boggle Solver Credit Todd Feldman for the original idea behind the assignment. Adapted from handouts of Julie Zelenski and Eric Roberts Boggle Solver The Boggle board is a 4x4 grid onto which you shake and randomly distribute 16 dice. These 6-sided dice have letters rather than numbers, creating a grid of letters from which you can form words. In the original version, the players start simultaneously and write down all the words they can find by tracing by a path through adjoining letters. Two letters adjoin if they are next to each other horizontally, vertically, or diagonally. There are up to eight letters adjoining a cube. A grid position can only be used once in the word. When time is called, duplicates are removed from the players' lists and the players receive points for their remaining words based on the word lengths. In this assignment, you will be creating a program that will find all the words on a boggle board This assignment is broken into two parts. The first part of the program will be creating a dictionary that can be used to store and look up words. This dictionary implementation will use a special tree called a prefix tree l Studio 201 27142 words loaded 27142 words loaded nter Board nter Board 0: a u CO :nin 1 2: o S a e 3: ma 1 e 0: a u CO 1: nl n 1 2: o S a e 3: ma 1 e Board (y)?: y Board (y)?: n of Words: 1 alane alans of Words: 2 n '11 alane unci uncia uncia uncial of Words: 3 a u C n 1'n1 uncials Assignment 3 - Boggle Solver Credit Todd Feldman for the original idea behind the assignment. Adapted from handouts of Julie Zelenski and Eric Roberts Boggle Solver The Boggle board is a 4x4 grid onto which you shake and randomly distribute 16 dice. These 6-sided dice have letters rather than numbers, creating a grid of letters from which you can form words. In the original version, the players start simultaneously and write down all the words they can find by tracing by a path through adjoining letters. Two letters adjoin if they are next to each other horizontally, vertically, or diagonally. There are up to eight letters adjoining a cube. A grid position can only be used once in the word. When time is called, duplicates are removed from the players' lists and the players receive points for their remaining words based on the word lengths. In this assignment, you will be creating a program that will find all the words on a boggle board This assignment is broken into two parts. The first part of the program will be creating a dictionary that can be used to store and look up words. This dictionary implementation will use a special tree called a prefix tree l Studio 201 27142 words loaded 27142 words loaded nter Board nter Board 0: a u CO :nin 1 2: o S a e 3: ma 1 e 0: a u CO 1: nl n 1 2: o S a e 3: ma 1 e Board (y)?: y Board (y)?: n of Words: 1 alane alans of Words: 2 n '11 alane unci uncia uncia uncial of Words: 3 a u C n 1'n1 uncials

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