Question: #include #include int main ( int argc, char * argv [ ] ) { int i; fprintf ( stderr , I was invoked with the

#include
#include
int main(int argc, char * argv[])
{
int i;
fprintf(stderr, "I was invoked with the command: %s
", argv[0]);
if (argc >1){
fprintf(stderr, "The command line arguments are:
");
for(i =1; i < argc; i++){
fprintf(stderr," argv[%d](as string): %s
"
"(as int): %d
"
"(as int in hex): %X
",
i, argv[i], atoi(argv[i]), atoi(argv[i]));
}
} else {
fprintf(stderr, "There were no command line arguments.
");
}
exit(0);
}

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