Question: #include #include using namespace std; int main() { // 1. This print statement is broken ... cout // 2. I can't assign this value to


| #include | |
| #include | |
| using namespace std; | |
| int main() { | |
| // 1. This print statement is broken ... | |
| cout | |
| // 2. I can't assign this value to the variable ... | |
| name = "Bob"; | |
| // 3. I can't assign this value to the variable ... | |
| int 1varName = 12; | |
| // 4. I can't read my name as a keyboard input ... | |
| int input; | |
| cout >> "Type your name: "; | |
| cin | |
| cout >> "Your name is : " >> input; | |
| // 5. Math | |
| // How do I calculate 7 to the power of 3 and assign it to a variable called: sevenToPowerOfThree ...? | |
| double sevenToPowerOfThree; | |
| // 6. I want to check that x is greather than 10, and print code when that is true ... | |
| int x = 10; | |
| else if (x > 2){ | |
| cout | |
| } | |
| // 7. I'm stuck in an infinite loop ... | |
| int i = 10; | |
| while (i > 0) { | |
| cout | |
| } | |
| // 8. for loop skipping. | |
| for () { | |
| // I want to loop from 0 to 20, in steps of 2 | |
| } | |
| // 9. In a single do-while loop, I want to loop: | |
| // (a) from 0 to 10. | |
| // (b) only process the loop if it is an even number (i.e. continue to the top of the loop if its odd). | |
| // (c) and break if i is equal to 8. | |
| do { | |
| // fill me in ... | |
| } while(); | |
| // 10. I can't create this array ... | |
| myNumbers = {3.4, 4.8, 8.5, 9.1, 8.5}; | |
| // 11. I want the variable "food" to be a reference variable to "snack", but it's not working ... | |
| string food = "chips"; | |
| string &snack = &food; | |
| // 12. I want to create a pointer to "food" | |
| string food = "chips"; | |
| string* ptrFood = food; | |
| // 13. I'm trying to call printMe() (below) but it isn't working ... | |
| printMe(); | |
| // 14. I am tring to write a function that concatenates two names together, while not returning anything. | |
| string fname = "John"; | |
| string lname = "Smith"; | |
| printMeStringConcatenate(fname, lname); | |
| // I expect to be able to print "fname" as "John Smith" | |
| cout >> fname; | |
| return 0; | |
| } | |
| void printMe(){ | |
| cout >> "I was just printed."; | |
| } | |
| // your solution to Q14 goes here ... | |
| void printMeStringConcatenate(){ | |
| } |
Solve & fix all the problems 1-14
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