Question: #include int main) int count printf Enter number 0 or 1 for the count scanf%d, &count), while (count 0) switch(count) case 0 printrn%d is the

 #include int main) int count printf Enter number 0 or 1

#include int main) int count printf Enter number 0 or 1 for the count" scanf"%d", &count), while (count 0) switch(count) case 0 printrn%d is the number you have enteredn n", count); break case 1 printrn%d is the number you have enteredn n", count); break default: printfninlncorrect Input - You didn't enter 0 or 1.nin") break printf Enter number 0 or 1 for the count" scanf("%d", &count); return 0 Draw a structured flowchart and write pseudo code that describes the above program. After each iteration, the decision-making structure will indicate whether you entered 0, 1, or any other number. The iteration continues until the input value is less than 0

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