Question: #include int main(void){ int j = 0; if(j == 0) { printf(j = %d ,j++); printf(j = %d ,j); } return(0); } a. j =

#include  
int main(void){
 int j = 0; 
 if(j == 0)
 {
 printf("j = %d ",j++);
 printf("j = %d ",j);
 } 
 return(0);
}
a.

j = 1

j = 1

j = 2

j = 2

....and so on

b.

Nothing

c.

None of the other answers are correct.

d.

j = 0

j = 1

e.

j =1

j = 1

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

Lets go through the given program step by step to determine the output Understanding the code The pr... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!