#include

using namespace std;

int main()

{

int N;

cin >> N;

int a = 0, b = 1, c;

if (N == 0)

cout

else if (N == 1)

cout

else

{

for (int i = 0; i

{

c = a + b;

a = b;

b = c;

cout

}

cout

}

return 0;

}

This code is the solution to the problem. Sorry about that.

Note, the first number in the pair is the iteration count (i) and the second number is the value of the (i+2)-th Fibonacci value Problem 4 Write the solution to problem 2 or 3 into a separate header and definition file and create a makefile to compile it into an executable. It will be tested by simply running 'make' in /lab2