Question: #include using namespace std; void function1(int n){ int count = 0; for(int x = 0; x < 12; x++){ cout <

#include

using namespace std;

void function1(int n){ int count = 0; for(int x = 0; x < 12; x++){ cout<<"counter:"<< count++<

void function2(int n){ int count = 0; for(int x = 0; x < n; x++){ cout<<"--- x="<

void function3(int n){ int count = 0; for(int x = 0; x < n; x++){ cout<<"--- x ="<

return 0; }

Run the time complexity.cpp, for different input n, i.e., n = 1, n = 10, n = 20, write down the final value of counter for function1, function2, and function3. Explain the result through step-by-step calculation.

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