Question: #include using namespace std; void function1(int n){ int count = 0; for(int x = 0; x < 12; x++){ cout <
#include
using namespace std;
void function1(int n){ int count = 0; for(int x = 0; x < 12; x++){ cout<<"counter:"<< count++< void function2(int n){ int count = 0; for(int x = 0; x < n; x++){ cout<<"--- x="< void function3(int n){ int count = 0; for(int x = 0; x < n; x++){ cout<<"--- x ="< return 0; } Run the time complexity.cpp, for different input n, i.e., n = 1, n = 10, n = 20, write down the final value of counter for function1, function2, and function3. Explain the result through step-by-step calculation.
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