Question: #include ( ( ( x ) ( N ) ) | ( ( x ) ( 8 * * s i z e o f

#include (((x)(N))|((x)(8**sizeof(x)-(N))))(((x)>(N))|((x)(8**sizeof(x)-(N))))ii=0;i4;i++%02xi32=0i,r=10r++i=0;i4;i++[i]??=
Draw a block diagram showing how the current hash.c works. How could you create collisions?
 #include (((x)(N))|((x)(8**sizeof(x)-(N))))(((x)>(N))|((x)(8**sizeof(x)-(N))))ii=0;i4;i++%02xi32=0i,r=10r++i=0;i4;i++[i]??= Draw a block diagram showing how the current hash.c

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