Question: int * numbers = new int [ 5 ] ; for ( int i = 0 ; i < = 4 ; i + +

int *numbers = new int[5];
for (int i =0; i <=4; i++)
*(numbers + i)= i;
cout << numbers[2]<< endl;
Group of answer choices
a. A memory address
b.1
c.2
d.3

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