Integrate the function.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{t^2\sqrt[\phantom{2}]{2-t^2}}dt$

A$.-\frac{\sqrt[\phantom{2}]{2-t^2}}{2t}C$

B$.\frac{\sqrt[\phantom{2}]{2-t^2}}{t}C$

c$.-\frac{\sqrt[\phantom{2}]{2-t^2}}{2t}si{n}^{-1}2tc$

D$.-\frac{\sqrt[\phantom{2}]{2-t^2}}{2t^2}c$