Integrate the function.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{t^2\sqrt[\phantom{2}]{4-t^2}}dt$

$-\frac{\sqrt[\phantom{2}]{4-t^2}}{4t}C$

$-\frac{\sqrt[\phantom{2}]{4-1^2}}{{42}^2}C$

$-\frac{\sqrt[\phantom{2}]{4-t^2}}{4t}si{n}^{-1}4tC$

$\frac{\sqrt[\phantom{2}]{4-t^2}}{t}C$