Internet Transport Layer protocols $($TCP and UDP$)$ use $1\text{'}$s complement for their checksums.

Suppose you have the following three $8-$bit bytes: $01010101,01110000,01001100.$

a$)$ What is the $1\text{'}$s complement of the sum of these $8-$bit bytes?

b$)$ With the $1\text{'}$s complement scheme, how does the receiver detect errors?

c$)$ Is it possible that a $1-$bit error will go undetected? How about a $2-$bit error?