Question: Internet Visit: A U.S. Web Usage Snapshot indicated a monthly average of 36 Internet visits a particular website per user from home. A random sample

Internet Visit: A U.S. Web Usage Snapshot indicated a monthly average of 36 Internet visits a particular website per user from home. A

random sample of 29 Internet users yielded a sample mean of 37.5

visits with a standard deviation of 5.3. At the 0.10 level of

signicance can it be concluded that this differs from the national average?

Assume the population is normally distributed. Use a TI-83 Plus/TI-84 Plus calculator:

Internet Visit: A U.S. Web Usage Snapshot indicated a monthly average of 36 Internet visits a particular website per user from home. A random sample of 29 Internet users yielded a sample mean of 37.5 visits with a standard deviation of 5.3. At the 0.10 level of signicance can it be concluded that this differs from the national average? Assume the population is normally distributed. Use a TI-83 Plus/TI-84 Plus calculator: (a) State the hypotheses and identify the claim. HOE] H.=_ (Choose one) V est. onetailed two-tailed This hypothesis test is a (b) Find the P-value. Round the answer to at least four decimal places. Part 3 of 4 (c) Make the decision. (Choose one) the null hypothesis. Reject X Do not rejectPart 4 of 4 (d) Summarize the results. There (Choose one) V enough evidence to support the claim that the mean is different from the national average. is is not

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