Question: (Intro to java help?) . For the TimeSpan class described below, add a compareTo method that takes another TimeSpan object as a parameter & returns:

(Intro to java help?)

. For the TimeSpan class described below, add a compareTo method that takes another TimeSpan object as a parameter & returns:

-1 if this TimeSpan is SMALLER than to the TimeSpan object passed in as a parameter

0 if both TimeSpans are the same

1 if this TimeSpan is GREATER than the TimeSpan object passed in as a parameter

Add code, as needed, to allow the Collections class to sort the ArrayList of TimeSpan objects

import java.util.*;

public class TimeSpan implements {

private int hours;

private int minutes;

public TimeSpan(int hours1, int minutes1) {

hours = 0;

minutes = 0;

add(hours1, minutes1);

}

public void add(int hours1, int minutes1) {

hours += hours1;

minutes += minutes1;

while (minutes > 60) {

minutes -= 60; // convert 60 min --> 1 hour

hours++;

}

}

public void add(TimeSpan time) {

add(time.hours, time.minutes);

}

public double getTotalHours() {

return hours + minutes / 60.0;

}

public String toString() {

return hours + "h-" + minutes + "m";

}

// *** Your method code here ***

public static void main(String[] args) {

TimeSpan t1 = new TimeSpan(4, 13);

TimeSpan t2 = new TimeSpan(5, 8);

TimeSpan t3 = new TimeSpan(3, 51);

TimeSpan t4 = new TimeSpan(6, 76);

TimeSpan t5 = new TimeSpan(1, 1);

ArrayList list = new ArrayList();

list.add(t1);

list.add(t2);

list.add(t3);

list.add(t4);

list.add(t5);

System.out.println(list);

Collections.sort(list);

System.out.println(list);

}

}

Expected Output: > run TimeSpan

[4h-13m, 5h-8m, 3h-51m, 7h-16m, 1h-1m]

[1h-1m, 3h-51m, 4h-13m, 5h-8m, 7h-16m]

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