INVERSE

$P_T^{\text{\#}1}$

$N=2,759\mathrm{.}76$

$E=3,291\mathrm{.}48$

$PT.{?}^{**2},N=1,281\mathrm{.}75$

$E=5,280\mathrm{.}00$

pr$.*2$

$N=1,281\mathrm{.}75$

FORWARD

$PT\frac{.}{\text{\#}}3N=13,789,426\mathrm{.}43$

$E=3,076,789\mathrm{.}10$

$BRG.PT.3ToP.T.=$

$N{27}^1{14}^{\text{'}}{37}^{W}W$

DisT $=528\mathrm{.}76$

FIND $PT\mathrm{.}4$ cooeds

Question says: solve the inverse problem between points $1$ and $2$ using given coordinates for points $1$ and $2($find the direction$($north azimuth and bearing distance$).$

Solve the forward problem using given coordinates and direction$/$distance$.$ Solve for the coordinate at point $4.$

Use decimal degree format for your calculations$($ decimal places$).$